11-71. A particular proton in space is subjected to two fields: a
gravitational field (1.30X105 N/kg toward planet X),
and
an electric field (2.47X10-4 N/C away from planet X).
(a) If the proton is released from rest, in which direction will
it move?
(b) After moving 1.50 m, what will be its speed? Use energy
methods
and assume uniform fields.
ACCUMULATED SOLUTION
FE = qE
Fg = mg
Fg = mg
= (1.673X10-27 )(1.3X105) = 2.175X10-22
N
FE = qE = (1.602X10-19
)(2.47X10-4) = 3.957X10-23 N
No. When an object is falling in a gravitational field (as the proton
is here) is the gravitational potential energy increasing
or decreasing?
Click on the answer.