10-49 An electron in an oscilloscope beam travels between the deflecting plates with an initial velocity of 2.0X107 m/s parallel to the plates, which lie in a horizontal plane. The electric field is 2.2X104 N/C downward, and the plates have a length of 4.0 cm. When the electron leaves the plates, (a) how far has it dropped or risen? (Specify which.) (b) what is its velocity (magnitude and direction)?
[Ans. (a) risen 7.7X10-3 m (b) 2.1X107 m/s at 21° above horizontal]



 
ACCUMULATED ANSWER

 


Correct!
Positive charges move with the field so negative charges move against the field.

 
 

The magnitude of the force on the electron is given by:
 

(A) F = q/E

(B) F = qE

(C) F = E/q