p = 10.0 cm, f = 12.0 cm
1/p + 1/q = 1/f
1/10 + 1/q = 1/12
1/q = 1/12 - 1/10 = -2/120
q = -120/2 = -60 cm.
Image is upstream and virtual. (Object is inside the focal length and the lens is operating as a simple magnifying glass)

Now find the magnification:
m = -q/p = -(-60)/10 = 6
i.e., Image is magnified and erect.

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