Yes!

For the 2nd lens:
p = -25 cm, f = -10 cm

1/p + 1/q = 1/f
1/-25 + 1/q = 1/-10
1/q = -1/10 + 1/25 = (10 - 25)/250 = -15/250
q = -250/15 = -16.7 cm

Therefore the final image is 16.7 cm to the left (upstream) of the 2nd lens or 16.7 - 5 = 11.7 cm to the left of the 1st lens.

Now find the magnification
For 1st lens: p1 = 15 cm, q1 = 30 cm
For 2nd lens: p2 = -25 cm, q2 = -16.7 cm
m1 = -q1/p1 = -30/15 = -2
m2 = -q2/p2 = -(-16.7)/(-25) = -0.668
m = m1m = (-2)(-0.668) = 1.34

Image size = m(Object Size) = 1.34X1 = 1.34 cm

Image is magnified and virtual

This is, in fact, the optical arrangement of the Galilean telescope used in opera glasses.

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