The only thing that relates directly to
sample length and concentration is the absorbance A = ecl,
so A must be found.
%T = 48, therefore I/I0 = 0.48
A = log(1/0.48) = 0.319 = ecl
If l is increased by a factor 3 then so must be the absorbance.
Anew = 3X0.319 = 0.956 = log I0/I
I0/I = 9.04
I/I0 = 0.11
%T = 11%
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