For R

For R_{2}: I_{2} = V / R_{2} = 10 / 3330
= 0.0030 A

There are 2 ways to determine the third and last current:

1. As before For R_{3}: I_{3} = V / R_{3}
= 10 / 147 = 0.068 A

Notice, as required: 0.04 + 0.0030 + 0.068 = 0.111 A

2. Knowing that the total current must be 0.111 A then

I_{3} = 0.111 - I_{1} - I_{2} = 0.111 - 0.04
- 0.0030 = 0.068 A as in 1.