The number declines from 1552 on day 3 to 40% lower than 852, i.e., 60% of 852 = 511.
511 = 1552e-0.209t
ln 511 = 1552 - 0.0209t
t = 5.32 days after day 3
i.e., 8.32 days after the present.
Find decay constant:
N/N0 = 1/3.5 = e-k6
ln (1/3.5) = -k6
k = 0.209 d-1
|
Nmax = 852e0.200(3) = 1552 The number declines from 1552 on day 3 to 40% lower than 852, i.e., 60% of 852 = 511.
511 = 1552e-0.209t |