**EXAMPLE
PROBLEM ON TORQUE: The Swinging Door**

**Question**

In a hurry to catch a cab, you rush through a frictionless swinging
door and onto the sidewalk. The force you extered on the door was 50N,
applied perpendicular to the plane of the door. The door is 1.0m wide.
Assuming that you pushed the door at its edge, what was the torque on the
swinging door (taking the hinge as the pivot point)?

**Hints**

- Where is the pivot point?
- What was the force applied?
- How far from the pivot point was the force applied?
- What was the angle between the door and the direction of force?

The pivot point is at the hinges of the door, opposite to
where you were pushing the door. The force you used was 50N, at a distance
1.0m from the pivot point. You hit the door perpendicular to its plane,
so the angle between the door and the direction of force was 90 degrees.
Since
- =
r x F = r F sin() |
Figure 1 Diagram of Example Problem 1 |

- = (1.0m) (50N) sin(90)

= 50 N m

Explanation of Torque

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