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Subject: Electricity (multiple choice questions)
Date: Wed, 29 Dec 2004 09:53:33 -0500
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<BODY text=3D#000000 vLink=3D#800080 aLink=3D#ff0000 link=3D#0000ff =
bgColor=3Dwhite>
<BLOCKQUOTE>
  <TABLE bgColor=3D#ffff00>
    <TBODY>
    <TR>
      <TD><B>Multiple Choice Online Test</B><BR>Indicate the correct =
answer by=20
        clicking on the button next to the numbers 1, 2, 3 or 4. There =
is only=20
        one correct answer per question. After you have answered=20
        <B><U>all</U></B> multiple choice questions compare your choices =
with=20
        the correct answers. </TD></TR></TBODY></TABLE>
  <HR width=3D"100%" color=3Dred SIZE=3D3>

  <CENTER>
  <H2>Electricity I</H2></CENTER>
  <HR width=3D"100%" color=3Dred SIZE=3D3>
  <BR>
  <FORM name=3DF><!frage1>
  <TABLE cellSpacing=3D0 cellPadding=3D0 border=3D0>
    <TBODY>
    <TR>
      <TD vAlign=3Dtop><B>1.) If a current of 3 A is divided by the =
following=20
        circuit, the current flowing through the 4 Ohm resistor is =85 =
</B><BR>
        <UL>
          <TABLE cellSpacing=3D0 cols=3D2 width=3D"90%" border=3D0>
            <TBODY>
            <TR>
              <TD width=3D50><B>1</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ1></TD>
              <TD>3 A</TD></TR>
            <TR>
              <TD width=3D50><B>2</B>&nbsp;<INPUT type=3Dradio value=3D1 =
name=3DQ1></TD>
              <TD>2 A</TD></TR>
            <TR>
              <TD width=3D50><B>3</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ1></TD>
              <TD>1,5 A</TD></TR>
            <TR>
              <TD width=3D50><B>4</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ1></TD>
              <TD>1 A</TD></TR></TBODY></TABLE><INPUT =
onclick=3D'gibfeedback("The electric current splits up according to the =
resistance (low resistance high current and high resistance low =
current). If 3 A flow into the parallel connection 2/3 of I (2/3 of 3A =
=3D 2A) will pass through the 4&#937; resistor and 1/3 of I (1/3 of 3A =
=3D 1A) through the 8&#937; resistor.")' type=3Dbutton =
value=3DExplanation>
          <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
           </UL></TD>
      <TD vAlign=3Dtop>
        <CENTER>&nbsp;<IMG height=3D178 alt=3Dpmcelec1.gif=20
        src=3D"http://www.sec.org.za/tests/pmcelec1.gif" width=3D480=20
        border=3D0>&nbsp;</CENTER></TD></TR></TBODY></TABLE>
  <P><!frage2>
  <TABLE>
    <TBODY>
    <TR>
      <TD><B>2.) The diagram at the right shows part of a circuit into =
which a=20
        current I is flowing. Which ammeter shows the highest =
reading?</B>=20
        <UL>
          <TABLE cellSpacing=3D0 cols=3D2 border=3D0>
            <TBODY>
            <TR>
              <TD width=3D50><B>1</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ2></TD>
              <TD>A<SUB>1</SUB></TD></TR>
            <TR>
              <TD width=3D50><B>2</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ2></TD>
              <TD>A<SUB>2</SUB></TD></TR>
            <TR>
              <TD width=3D50><B>3</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ2></TD>
              <TD>A<SUB>3</SUB></TD></TR>
            <TR>
              <TD width=3D50><B>4</B>&nbsp;<INPUT type=3Dradio value=3D1 =
name=3DQ2></TD>
              <TD>All three ammeters give the same =
reading</TD></TR></TBODY></TABLE><INPUT onclick=3D'gibfeedback("Since =
the total resistance is the same (2&#937; + 8&#937; =3D 10&#937;) in =
both parts of the parallel connection all ammeters will show the same =
reading.")' type=3Dbutton value=3DExplanation>
          <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
           </UL></TD>
      <TD vAlign=3Dtop>
        <CENTER><IMG height=3D192 alt=3Dpmcelec2.gif=20
        src=3D"http://www.sec.org.za/tests/pmcelec2.gif" width=3D530=20
        =
border=3D0></CENTER></TD></TR></TBODY></TABLE><!&Omega;><!frage3>
  <TABLE>
    <TBODY>
    <TR>
      <TD vAlign=3Dtop><B>3.) The diagram to the right represents a part =
of a=20
        circuit containing an ohmic resistor, a voltmeter and an =
ammeter. If the=20
        reading on the ammeter A increases the reading on voltmeter V =
=85 </B>
        <UL>
          <TABLE cellSpacing=3D0 cols=3D2 border=3D0>
            <TBODY>
            <TR>
              <TD><B>1</B>&nbsp;<INPUT type=3Dradio value=3D1 =
name=3DQ3></TD>
              <TD>increases in the same ratio.</TD></TR>
            <TR>
              <TD><B>2</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ3></TD>
              <TD>increases, but not in the same ratio.</TD></TR>
            <TR>
              <TD><B>3</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ3></TD>
              <TD>remains unchanged.</TD></TR>
            <TR>
              <TD><B>4</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ3></TD>
              <TD>decreases in the same ratio. =
</TD></TR></TBODY></TABLE><INPUT onclick=3D'gibfeedback("Ohm=B4s Law: =
the current flowing through a conductor is directly proportional to the =
potential difference across it provided the temperature of the conductor =
remains constant. Or in formulae form: R =3D I/V, to keep R constant I =
and V have to increase/decrease at the same ratio.")' type=3Dbutton =
value=3DExplanation>=20
        </UL></TD>
      <TD><IMG height=3D152 alt=3Dpmcelec3.gif=20
        src=3D"http://www.sec.org.za/tests/pmcelec3.gif" width=3D300=20
    border=3D0></TD></TR></TBODY></TABLE>
  <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>

  <UL></UL>
  <P><!frage4><B>4.) A battery is connected to two identical light bulbs =
in=20
  parallel as well as another identical bulb in series. An ammeter and a =

  voltmeter are also connected as shown in the circuit diagram below. =
<BR>
  <CENTER><IMG height=3D158 alt=3Dpmcelec4.gif=20
  src=3D"http://www.sec.org.za/tests/pmcelec4.gif" width=3D550 =
border=3D0></CENTER>One=20
  of the light bulbs connected in parallel is unscrewed. How will the =
ammeter=20
  and the voltmeter readings change?</B>=20
  <UL>
    <TABLE border=3D0>
      <TBODY>
      <TR>
        <TD>&nbsp;</TD>
        <TD align=3Dmiddle><B>&nbsp;&nbsp;&nbsp;Voltmeter=20
          reading&nbsp;&nbsp;&nbsp;</B></TD>
        <TD align=3Dmiddle><B>&nbsp;&nbsp;&nbsp;Ammeter=20
          reading&nbsp;&nbsp;&nbsp;</B></TD></TR>
      <TR>
        <TD><B>1</B>&nbsp;<INPUT type=3Dradio value=3D0 name=3DQ4></TD>
        <TD align=3Dmiddle>increases</TD>
        <TD align=3Dmiddle>increases</TD></TR>
      <TR>
        <TD><B>2</B>&nbsp;<INPUT type=3Dradio value=3D1 name=3DQ4></TD>
        <TD align=3Dmiddle>increases</TD>
        <TD align=3Dmiddle>decreases</TD></TR>
      <TR>
        <TD><B>3</B>&nbsp;<INPUT type=3Dradio value=3D0 name=3DQ4></TD>
        <TD align=3Dmiddle>increases</TD>
        <TD align=3Dmiddle>unchanged</TD></TR>
      <TR>
        <TD><B>4</B>&nbsp;<INPUT type=3Dradio value=3D0 name=3DQ4></TD>
        <TD align=3Dmiddle>decreases</TD>
        <TD align=3Dmiddle>decreases</TD></TR></TBODY></TABLE><INPUT =
onclick=3D'gibfeedback("Unsrewing one of the parallel bulbs will change =
the total resistance of the circuit in a way that it goes up. Higher =
resistance will cause a lower current to flow through the circuit =
(option 2 and 4). How is the p.d. affected? Prior to unscrewing the =
voltmeter measured the p.d. across one of the bulbs connected in =
parallel, which had a lower resistance since they were in parallel =
(1/R<sub>total</sub> =3D 1/R<sub>1</sub> + 1/R<sub>2</sub>). After =
unscrewing a higher voltage is required to drive the current through the =
bulb =BB voltmeter reading goes up.")' type=3Dbutton =
value=3DExplanation>
    <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
     </UL><!frage5>
  <TABLE border=3D0>
    <TBODY>
    <TR>
      <TD vAlign=3Dtop><B>5.) A learner connects a circuit as shown in =
the=20
        diagram to the right. He/she uses a source of electricity with =
an=20
        electromotive force (emf) of 12 V. <BR>Which one of the =
following best=20
        gives the ammeter and voltmeter readings which the learner is =
most=20
        likely to get with this circuit? </B>
        <UL>
          <TABLE width=3D410 border=3D0>
            <TBODY>
            <TR>
              <TD width=3D50></TD>
              <TD align=3Dmiddle width=3D180><B>Ammeter reading</B></TD>
              <TD align=3Dmiddle width=3D180><B>Voltmeter =
reading</B></TD></TR>
            <TR>
              <TD width=3D50><B>1</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ5></TD>
              <TD align=3Dmiddle width=3D180>reads zero</TD>
              <TD align=3Dmiddle width=3D180>reads zero</TD></TR>
            <TR>
              <TD width=3D50><B>2</B>&nbsp;<INPUT type=3Dradio value=3D1 =
name=3DQ5></TD>
              <TD align=3Dmiddle width=3D180>reads zero</TD>
              <TD align=3Dmiddle width=3D180>reads 12 V</TD></TR>
            <TR>
              <TD width=3D50><B>3</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ5></TD>
              <TD align=3Dmiddle width=3D180>very large reading</TD>
              <TD align=3Dmiddle width=3D180>reads zero</TD></TR>
            <TR>
              <TD width=3D50><B>4</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ5></TD>
              <TD align=3Dmiddle width=3D180>very large reading</TD>
              <TD align=3Dmiddle width=3D180>reads 12 =
V</TD></TR></TBODY></TABLE><INPUT onclick=3D'gibfeedback("No current =
will flow in the circuit due to the position of the voltmeter. =
Voltmeters have a very high resistance - ammeters on the other hand have =
a very low resistance - and hence we can say that the resistance of the =
voltmeter <i>blocks somehow the current</i>. Since the voltmeter is =
connected across the terminals of the source of electricity it will =
measure the emf of the battery.")' type=3Dbutton value=3DExplanation>
          <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
           </UL></TD>
      <TD vAlign=3Dtop><IMG height=3D220 alt=3Dpmcelec5.gif=20
        src=3D"http://www.sec.org.za/tests/pmcelec5.gif" width=3D300 =
border=3D0>=20
    </TD></TR></TBODY></TABLE><!&Omega;><!frage6>
  <TABLE cellSpacing=3D0 cellPadding=3D3 width=3D"90%" border=3D0>
    <TBODY>
    <TR>
      <TD vAlign=3Dtop><B>6.) Three identical resistors of 4 <FONT=20
        face=3Dsymbol>W</FONT> are connected to give a combined =
resistance of 6=20
        <FONT face=3Dsymbol>W</FONT>. Which of the following circuit =
diagrams=20
        illustrates how this was done?</B> <BR><BR><BR><BR>
        <UL>
          <TABLE cellSpacing=3D0 cols=3D2 width=3D"90%" border=3D0>
            <TBODY>
            <TR>
              <TD width=3D50><B>1</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ6></TD>
              <TD><B>I</B></TD></TR>
            <TR>
              <TD width=3D50><B>2</B>&nbsp;<INPUT type=3Dradio value=3D1 =
name=3DQ6></TD>
              <TD><B>II</B></TD></TR>
            <TR>
              <TD width=3D50><B>3</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ6></TD>
              <TD><B>III</B></TD></TR>
            <TR>
              <TD width=3D50><B>4</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ6></TD>
              <TD><B>IV</B></TD></TR></TBODY></TABLE><INPUT =
onclick=3D'gibfeedback("Only in option 2 the effective resistance is =
6&#937;: 4&#937; and 4&#937; in parallel - 1/R =3D 1/4 + 1/4 =3D 1/2 =
hence R =3D 2&#937;. 4&#937; is in series with 2&#937; hence R combined =
=3D 2&#937; + 4&#937; =3D 6&#937;.")' type=3Dbutton value=3DExplanation>
          <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
           </UL></TD>
      <TD>
        <CENTER>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<IMG height=3D354=20
        alt=3Dpmcelec6.gif =
src=3D"http://www.sec.org.za/tests/pmcelec6.gif"=20
        width=3D570 border=3D0></CENTER></TD></TR></TBODY></TABLE>
  <P><!frage7>
  <TABLE>
    <TBODY>
    <TR>
      <TD vAlign=3Dtop><B>7.) In the circuit to the right B<SUB>1</SUB>, =

        B<SUB>2</SUB> and B<SUB>3</SUB> are identical light bulbs. The =
internal=20
        resistance of the battery can be ignored. <BR>Which statement is =
true=20
        regarding the relative brightness of the bulbs? <BR>
        <UL>
          <TABLE cellSpacing=3D0 cols=3D2 width=3D"90%" border=3D0>
            <TBODY>
            <TR>
              <TD width=3D50><B>1</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ7></TD>
              <TD>The three bulbs glow with the same =
brightness.</TD></TR>
            <TR>
              <TD width=3D50><B>2</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ7></TD>
              <TD>B<SUB>2</SUB> and B<SUB>3</SUB> glow with the same=20
                brightness but brighter than B<SUB>1</SUB>.</TD></TR>
            <TR>
              <TD width=3D50><B>3</B>&nbsp;<INPUT type=3Dradio value=3D1 =
name=3DQ7></TD>
              <TD>B<SUB>2</SUB> and B<SUB>3</SUB> glow with the same=20
                brightness but less brightly than =
B<SUB>1</SUB>.</TD></TR>
            <TR>
              <TD width=3D50><B>4</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ7></TD>
              <TD>B<SUB>1</SUB> glows brighter than B<SUB>2</SUB> while=20
                B<SUB>2</SUB> in turn glows brighter than B<SUB>3</SUB>. =

            </TD></TR></TBODY></TABLE><INPUT =
onclick=3D'gibfeedback("B<sub>2</sub> and B<sub>3</sub> are connected in =
parallel, hence only 50% of the current will flow through each of those =
bulbs and the p.d. across them will be less than the p.d. across =
B<sub>1</sub> (1/3 of total p.d. will be across B<sub>2</sub> and =
B<sub>3</sub>; 2/3 of total p.d. across B<sub>1</sub>). As a result =
B<sub>1</sub> will shine brightest (power =3D current <small>x</small> =
voltage) and B<sub>2</sub> and B<sub>3</sub> will have the same =
brightness. ")' type=3Dbutton value=3DExplanation>
          <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
           </UL></B></TD>
      <TD>&nbsp;&nbsp;<IMG height=3D199 alt=3Dpmcelec7.gif=20
        src=3D"http://www.sec.org.za/tests/pmcelec7.gif" width=3D350=20
    border=3D0></TD></TR></TBODY></TABLE>
  <P><!frage8>
  <TABLE>
    <TBODY>
    <TR>
      <TD vAlign=3Dtop width=3D"50%"><B>8.) Two identical light bulbs, X =
and Y,=20
        are connected in series as shown in the sketch to the right. =
<BR>How=20
        will the brightness of the bulbs change if switch S is closed? =
</B>
        <UL>
          <TABLE cellSpacing=3D0 cols=3D3 border=3D0>
            <TBODY>
            <TR>
              <TD width=3D50>&nbsp;&nbsp;</TD>
              <TD align=3Dmiddle width=3D100><B>X</B></TD>
              <TD align=3Dmiddle width=3D100><B>Y</B></TD></TR>
            <TR>
              <TD width=3D50><B>1</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ8></TD>
              <TD align=3Dmiddle width=3D100>
                <CENTER>brighter</CENTER></TD>
              <TD align=3Dmiddle width=3D100>
                <CENTER>brighter</CENTER></TD></TR>
            <TR>
              <TD width=3D50><B>2</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ8></TD>
              <TD align=3Dmiddle width=3D100>
                <CENTER>dimmer</CENTER></TD>
              <TD align=3Dmiddle width=3D100>
                <CENTER>dimmer</CENTER></TD></TR>
            <TR>
              <TD width=3D50><B>3</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ8></TD>
              <TD align=3Dmiddle width=3D100>
                <CENTER>brighter</CENTER></TD>
              <TD align=3Dmiddle width=3D100>not lit up</TD></TR>
            <TR>
              <TD width=3D50><B>4</B>&nbsp;<INPUT type=3Dradio value=3D1 =
name=3DQ8></TD>
              <TD align=3Dmiddle width=3D100>
                <CENTER>not lit up</CENTER></TD>
              <TD align=3Dmiddle width=3D100>
                =
<CENTER>brighter</CENTER></TD></TR></TBODY></TABLE><INPUT =
onclick=3D'gibfeedback("After closing the switch no current will flow =
through X, hence it will not lit up (option 4) and consequently a hgher =
current will pass through bulb Y making it shine brighter.")' =
type=3Dbutton value=3DExplanation>
          <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
           </UL></TD>
      <TD vAlign=3Dtop>&nbsp;&nbsp;
        <CENTER><IMG height=3D196 alt=3Dpmcelec8.gif=20
        src=3D"http://www.sec.org.za/tests/pmcelec8.gif" width=3D340=20
        border=3D0></CENTER></TD></TR></TBODY></TABLE><!frage9>
  <TABLE>
    <TBODY>
    <TR>
      <TD vAlign=3Dtop><B>9.) A student connects three identical =
resistors as=20
        shown in the sketch to the right. <BR>The potential difference =
across=20
        the battery is 12 Volt. What are the readings on V<SUB>1</SUB> =
and=20
        V<SUB>2</SUB> respectively? </B>
        <UL>
          <TABLE cellSpacing=3D0 cols=3D3 width=3D150 border=3D0>
            <TBODY>
            <TR>
              <TD width=3D50>&nbsp;</TD>
              <TD align=3Dmiddle width=3D50>
                <CENTER><B>V<SUB>1</SUB></B></CENTER></TD>
              <TD align=3Dmiddle width=3D50>
                <CENTER><B>V<SUB>2</SUB></B></CENTER></TD></TR>
            <TR>
              <TD width=3D50><B>1</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ9></TD>
              <TD align=3Dmiddle width=3D50>
                <CENTER><B>4</B></CENTER></TD>
              <TD align=3Dmiddle width=3D50>
                <CENTER><B>8</B></CENTER></TD></TR>
            <TR>
              <TD width=3D50><B>2</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ9></TD>
              <TD align=3Dmiddle width=3D50>
                <CENTER><B>6</B></CENTER></TD>
              <TD align=3Dmiddle width=3D50>
                <CENTER><B>6</B></CENTER></TD></TR>
            <TR>
              <TD width=3D50><B>3</B>&nbsp;<INPUT type=3Dradio value=3D1 =
name=3DQ9></TD>
              <TD align=3Dmiddle width=3D50>
                <CENTER><B>8</B></CENTER></TD>
              <TD align=3Dmiddle width=3D50>
                <CENTER><B>4</B></CENTER></TD></TR>
            <TR>
              <TD width=3D50><B>4</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ9></TD>
              <TD align=3Dmiddle width=3D50>
                <CENTER><B>9</B></CENTER></TD>
              <TD align=3Dmiddle width=3D50>
                =
<CENTER><B>3</B></CENTER></TD></TR></TBODY></TABLE><INPUT =
onclick=3D'gibfeedback("Correct answer is option 3 (see also question 6 =
&amp; 7): 2/3 of total p.d. will be across single resistor R and 1/3 of =
total p.d. will be measured across resistors R in parallel by =
V<sub>2</sub>.<br>2/3 =B7 12V =3D 8V; <br>and <br>1/3 =B7 12V =3D 4V =
across R in parallel.")' type=3Dbutton value=3DExplanation>
          <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
           </UL></TD>
      <TD>
        <CENTER>&nbsp;<IMG height=3D171 alt=3Dpmcelec9.gif=20
        src=3D"http://www.sec.org.za/tests/pmcelec9.gif" width=3D400=20
        =
border=3D0>&nbsp;</CENTER></TD></TR></TBODY></TABLE><!frage10><B>10.) A =
9 V=20
  battery is composed of six 1,5 V cells, which are connected in series. =
Each=20
  cell has an internal resistance of 0,2 <FONT face=3Dsymbol>W</FONT>. =
What is the=20
  highest current that can be obtained from such a battery? </B>
  <UL>
    <TABLE cellSpacing=3D0 cols=3D2 width=3D"90%" border=3D0>
      <TBODY>
      <TR>
        <TD width=3D50><B>1</B>&nbsp;<INPUT type=3Dradio value=3D1 =
name=3DQ10></TD>
        <TD><B>7,5 A</B></TD></TR>
      <TR>
        <TD width=3D50><B>2</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ10></TD>
        <TD><B>1,5 A</B></TD></TR>
      <TR>
        <TD width=3D50><B>3</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ10></TD>
        <TD><B>1,2 A</B></TD></TR>
      <TR>
        <TD width=3D50><B>4</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ10></TD>
        <TD><B>0,3 A</B></TD></TR></TBODY></TABLE><INPUT =
onclick=3D'gibfeedback("Total internal resistance =3D 6 =B7 0,2&#937; =
=3D 1,2&#937;<br>Voltage =3D 9V<br> I =3D V/R =3D 9/1,2 =3D 7,5A.")' =
type=3Dbutton value=3DExplanation>
    <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
     </UL>
  <HR color=3Dblue SIZE=3D5>

  <CENTER>
  <TABLE cellSpacing=3D0 cols=3D1 width=3D"60%" border=3D1>
    <CAPTION><B>Results</B></CAPTION>
    <TBODY>
    <TR>
      <TD>
        <CENTER><INPUT type=3Dhidden value=3Dfalse =
name=3Dbearbeitet><INPUT onclick=3Dshow() type=3Dbutton value=3D"See =
your results" name=3DButton></CENTER></TD></TR>
    <TR>
      <TD>
        <CENTER><TEXTAREA name=3Dergebnis rows=3D3 readOnly =
cols=3D50></TEXTAREA></CENTER></TD></TR>
    <TR>
      <TD>
        <CENTER><INPUT onclick=3Dshowcorrect() type=3Dbutton =
value=3D"What are the correct answers?" =
name=3DButton></CENTER></TD></TR></TBODY></TABLE></CENTER></FORM>
  <TABLE cellPadding=3D5 width=3D"60%" border=3D1>
    <TBODY>
    <TR>
      <TD><FONT color=3D#9933ff>Hint: You can do the test offline as =
well. Just=20
        click "file" from the menu, then "save" to a destination of your =
choice.=20
        But remember to open file either with windows explorer or =
internet=20
        explorer. Netscape might not be able to reload pictures offline. =

      </FONT></TD></TR></TBODY></TABLE><B>
  <DIV align=3Dright><A href=3D"http://www.sec.org.za/trmc.html">click =
here for more=20
  multiple choice questions</A></DIV></B>
  <CENTER><IMG height=3D7 alt=3D"" =
src=3D"http://www.sec.org.za/physics/XBAR06.GIF"=20
  width=3D"100%" border=3D0></CENTER>
  <TABLE cellSpacing=3D0 cellPadding=3D3 width=3D"86%" align=3Dcenter =
bgColor=3D#99ffff=20
  border=3D0 valign=3D"center">
    <TBODY>
    <TR>
      <TD align=3Dmiddle width=3D"16%"><A=20
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href=3D"http://www.sec.org.za/index.html"><B><SMALL>Home</SMALL></B></A><=
/TD>
      <TD align=3Dmiddle width=3D"17%"><A=20
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href=3D"http://www.sec.org.za/trmat.html"><B><SMALL>Maths</SMALL></B></A>=
</TD>
      <TD align=3Dmiddle width=3D"17%"><A=20
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href=3D"http://www.sec.org.za/trphy.html"><B><SMALL>Physics</SMALL></B></=
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------=_NextPart_000_0024_01C4ED8C.41F1B360--
