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Subject: Electricity (multiple choice questions)
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<BODY text=3D#000000 vLink=3D#800080 aLink=3D#ff0000 link=3D#0000ff =
bgColor=3Dwhite>
<BLOCKQUOTE>
  <TABLE bgColor=3D#ffff00>
    <TBODY>
    <TR>
      <TD><B>Multiple Choice Online Test</B><BR>Indicate the correct =
answer by=20
        clicking on the button next to the letters A, B, C or D. There =
is only=20
        one correct answer per question. After you have answered=20
        <B><U>all</U></B> multiple choice questions compare your choices =
with=20
        the correct answers. </TD></TR></TBODY></TABLE>
  <HR width=3D"100%" color=3Dred SIZE=3D3>

  <CENTER>
  <H2>Electricity II</H2></CENTER>
  <HR width=3D"100%" color=3Dred SIZE=3D3>
  <BR>
  <FORM name=3DF><!frage1>
  <TABLE cellSpacing=3D0 cellPadding=3D0 border=3D0>
    <TBODY>
    <TR>
      <TD vAlign=3Dtop><B><FONT color=3Dred>1.)</FONT> Consider the =
electric=20
        circuit shown in the diagram at the right.<BR>The reading on the =

        voltmeter V is ... </B>
        <P>
        <TABLE cellSpacing=3D0 border=3D0>
          <TBODY>
          <TR>
            <TD width=3D50><B>A</B> <INPUT type=3Dradio value=3D0 =
name=3DQ1></TD>
            <TD>
              <CENTER>0 V</CENTER></TD></TR>
          <TR>
            <TD width=3D50><B>B</B> <INPUT type=3Dradio value=3D1 =
name=3DQ1></TD>
            <TD>
              <CENTER>2 V</CENTER></TD></TR>
          <TR>
            <TD width=3D50><B>C</B> <INPUT type=3Dradio value=3D0 =
name=3DQ1></TD>
            <TD>
              <CENTER>4 V</CENTER></TD></TR>
          <TR>
            <TD width=3D50><B>D</B> <INPUT type=3Dradio value=3D0 =
name=3DQ1></TD>
            <TD>
              <CENTER>6 V</CENTER></TD></TR></TBODY></TABLE><!-- <input =
type=3D"button" value=3D"Explanation" onclick=3D'gibfeedback("The =
electric current splits up according to the resistance (low resistance =
high current and high resistance low current). If 3 A flow into the =
parallel connection 2/3 of I (2/3 of 3A =3D 2A) will pass through the =
4&Omega; resistor and 1/3 of I (1/3 of 3A =3D 1A) through the 8&Omega; =
resistor.")'>
 -->
        <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
        </P></TD>
      <TD vAlign=3Dtop>
        <CENTER><IMG height=3D206 alt=3D"electricity II, diagram 1"=20
        src=3D"http://www.sec.org.za/tests/pmcelecb01.gif" width=3D381=20
        border=3D0></CENTER></TD></TR></TBODY></TABLE>
  <P><!frage2><B><FONT color=3Dred>2.)</FONT> Two light bulbs P and Q =
are=20
  identical in all respects, except that P's filament is thicker than =
Q's. If=20
  the same potential difference is applied to each, then =85 </B>
  <P>
  <TABLE cellSpacing=3D0 border=3D0>
    <TBODY>
    <TR>
      <TD width=3D50><B>A</B><INPUT type=3Dradio value=3D0 =
name=3DQ2></TD>
      <TD width=3D550>P will burn brighter because it has the greater=20
      resistance.</TD></TR>
    <TR>
      <TD width=3D50><B>B</B><INPUT type=3Dradio value=3D0 =
name=3DQ2></TD>
      <TD width=3D550>Q will burn brighter because it has the greater=20
      resistance.</TD></TR>
    <TR>
      <TD width=3D50><B>C</B><INPUT type=3Dradio value=3D1 =
name=3DQ2></TD>
      <TD width=3D550>P will burn brighter because it has the lower=20
      resistance.</TD></TR>
    <TR>
      <TD width=3D50><B>D</B><INPUT type=3Dradio value=3D0 =
name=3DQ2></TD>
      <TD width=3D550>Q will burn brighter because it has the lower=20
      resistance.</TD></TR></TBODY></TABLE><!-- <input type=3D"button" =
value=3D"Explanation" onclick=3D'gibfeedback("Since the total resistance =
is the same (2&Omega; + 8&Omega; =3D 10&Omega;) in both parts of the =
parallel connection all ammeters will show the same reading.")'>
 -->
  <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
<!&Omega;>
  <P><!frage3>
  <TABLE>
    <TBODY>
    <TR>
      <TD vAlign=3Dtop width=3D"90%"><B><FONT color=3Dred>3.)</FONT> The =
ammeter and=20
        the battery in the sketch to the right have negligible =
resistance. The=20
        resistors are in parallel. What will happen to the ammeter and =
voltmeter=20
        readings when switch S is closed? </B>
        <P>
        <TABLE cellSpacing=3D0 cols=3D3 border=3D0>
          <TBODY>
          <TR>
            <TD>&nbsp;</TD>
            <TD>
              <CENTER><B>ammeter reading</B></CENTER></TD>
            <TD>
              <CENTER><B>voltmeter reading</B></CENTER></TD></TR>
          <TR>
            <TD width=3D50><B>A</B><INPUT type=3Dradio value=3D1 =
name=3DQ3></TD>
            <TD width=3D120>
              <CENTER>increases</CENTER></TD>
            <TD width=3D120>
              <CENTER>unchanged</CENTER></TD></TR>
          <TR>
            <TD width=3D50><B>B</B><INPUT type=3Dradio value=3D0 =
name=3DQ3></TD>
            <TD width=3D120>
              <CENTER>increases</CENTER></TD>
            <TD width=3D120>
              <CENTER>increases</CENTER></TD></TR>
          <TR>
            <TD width=3D50><B>C</B><INPUT type=3Dradio value=3D0 =
name=3DQ3></TD>
            <TD width=3D120>
              <CENTER>decreases</CENTER></TD>
            <TD width=3D120>
              <CENTER>decreases</CENTER></TD></TR>
          <TR>
            <TD width=3D50><B>D</B><INPUT type=3Dradio value=3D0 =
name=3DQ3></TD>
            <TD width=3D120>
              <CENTER>decreases</CENTER></TD>
            <TD width=3D120>
              =
<CENTER>increases</CENTER></TD></TR></TBODY></TABLE></P></TD>
      <TD vAlign=3Dtop>
        <CENTER><IMG height=3D248 alt=3D"electricity II, diagram 2"=20
        src=3D"http://www.sec.org.za/tests/pmcelecb02.gif" width=3D314=20
        border=3D0></CENTER></TD></TR></TBODY></TABLE><!-- <input =
type=3D"button" value=3D"Explanation" =
onclick=3D'gibfeedback("Ohm&acute;s Law: the current flowing through a =
conductor is directly proportional to the potential difference across it =
provided the temperature of the conductor remains constant. Or in =
formulae form: R =3D I/V, to keep R constant I and V have to =
increase/decrease at the same ratio.")'>
 -->
  <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>

  <P><!frage4><B><FONT color=3Dred>4.)</FONT> In the circuit shown the =
bulb marked=20
  2R has twice the resistance of the bulb marked R. Compared with bulb =
2R, the=20
  current in bulb R and its brightness compared to the other bulb, is =
=85 </B>
  <TABLE>
    <TBODY>
    <TR>
      <TD>
        <TABLE cellSpacing=3D0 border=3D0>
          <TBODY>
          <TR>
            <TD width=3D50>&nbsp;</TD>
            <TD align=3Dmiddle width=3D115><B>current in R</B></TD>
            <TD align=3Dmiddle width=3D135><B>brightness in =
2R</B></TD></TR>
          <TR>
            <TD width=3D50><B>A</B><INPUT type=3Dradio value=3D0 =
name=3DQ4></TD>
            <TD align=3Dmiddle>larger</TD>
            <TD align=3Dmiddle>brighter</TD></TR>
          <TR>
            <TD width=3D50><B>B</B><INPUT type=3Dradio value=3D1 =
name=3DQ4></TD>
            <TD align=3Dmiddle>larger</TD>
            <TD align=3Dmiddle>dimmer</TD></TR>
          <TR>
            <TD width=3D50><B>C</B><INPUT type=3Dradio value=3D0 =
name=3DQ4></TD>
            <TD align=3Dmiddle>smaller</TD>
            <TD align=3Dmiddle>brighter</TD></TR>
          <TR>
            <TD width=3D50><B>D</B><INPUT type=3Dradio value=3D0 =
name=3DQ4></TD>
            <TD align=3Dmiddle>smaller</TD>
            <TD align=3Dmiddle>dimmer</TD></TR></TBODY></TABLE><!-- =
<input type=3D"button" value=3D"Explanation" =
onclick=3D'gibfeedback("Unsrewing one of the parallel bulbs will change =
the total resistance of the circuit in a way that it goes up. Higher =
resistance will cause a lower current to flow through the circuit =
(option 2 and 4). How is the p.d. affected? Prior to unscrewing the =
voltmeter measured the p.d. across one of the bulbs connected in =
parallel, which had a lower resistance since they were in parallel =
(1/R<sub>total</sub> =3D 1/R<sub>1</sub> + 1/R<sub>2</sub>). After =
unscrewing a higher voltage is required to drive the current through the =
bulb &raquo; voltmeter reading goes up.")'>
 -->
        <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
      </TD>
      <TD vAlign=3Dtop align=3Dmiddle><IMG height=3D191=20
        alt=3D"electricity II, diagram 3"=20
        src=3D"http://www.sec.org.za/tests/pmcelecb03.gif" width=3D346 =
border=3D0>=20
    </TD></TR></TBODY></TABLE>
  <P><!frage5><B><FONT color=3Dred>5.)</FONT> Thabiseng connected four =
identical=20
  light bulbs in a circuit as shown to the right. She observes that the=20
  brightness of bulb A varies if some of the switches are closed. In =
which case=20
  will bulb A burn brightest? </B>
  <TABLE width=3D"90%" border=3D0>
    <TBODY>
    <TR>
      <TD>
        <TABLE border=3D0>
          <TBODY>
          <TR>
            <TD width=3D50><B>A</B><INPUT type=3Dradio value=3D0 =
name=3DQ5></TD>
            <TD>S<SUB>1</SUB> closed with S<SUB>2</SUB> and =
S<SUB>3</SUB>=20
            open</TD></TR>
          <TR>
            <TD width=3D50><B>B</B><INPUT type=3Dradio value=3D0 =
name=3DQ5></TD>
            <TD>S<SUB>1</SUB> and S<SUB>2</SUB> closed with =
S<SUB>3</SUB>=20
            open</TD></TR>
          <TR>
            <TD width=3D50><B>C</B><INPUT type=3Dradio value=3D1 =
name=3DQ5></TD>
            <TD>S<SUB>1</SUB>, S<SUB>2</SUB> and S<SUB>3</SUB> =
closed</TD></TR>
          <TR>
            <TD width=3D50><B>D</B><INPUT type=3Dradio value=3D0 =
name=3DQ5></TD>
            <TD>S<SUB>1</SUB>, S<SUB>2</SUB> and S<SUB>3</SUB>=20
          open</TD></TR></TBODY></TABLE><!-- <input type=3D"button" =
value=3D"Explanation" onclick=3D'gibfeedback("No current will flow in =
the circuit due to the position of the voltmeter. Voltmeters have a very =
high resistance - ammeters on the other hand have a very low resistance =
- and hence we can say that the resistance of the voltmeter <i>blocks =
somehow the current</i>. Since the voltmeter is connected across the =
terminals of the source of electricity it will measure the emf of the =
battery.")'>
 -->
        <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
      </TD>
      <TD vAlign=3Dtop><IMG height=3D262 alt=3D"electricity II, diagram =
4"=20
        src=3D"http://www.sec.org.za/tests/pmcelecb04.gif" width=3D337 =
border=3D0>=20
    </TD></TR></TBODY></TABLE><!&Omega;>
  <P><!frage6><B><FONT color=3Dred>6.)</FONT> Two identical light bulbs =
X and Y,=20
  which are rated at 60 W; 240 V, are connected in series to a 240 V =
source as=20
  shown in the diagram below. If point A in the circuit is now connected =
to=20
  point B by a piece of copper wire with very low resistance, how will =
the=20
  brightness of each bulb change? </B>
  <TABLE width=3D"90%">
    <TBODY>
    <TR>
      <TD>
        <TABLE cellSpacing=3D0 border=3D0>
          <TBODY>
          <TR>
            <TD width=3D50><B>A</B><INPUT type=3Dradio value=3D0 =
name=3DQ6></TD>
            <TD>Both X and Y will burn brighter.</TD></TR>
          <TR>
            <TD width=3D50><B>B</B><INPUT type=3Dradio value=3D0 =
name=3DQ6></TD>
            <TD>Both X and Y will burn less brightly.</TD></TR>
          <TR>
            <TD width=3D50><B>C</B><INPUT type=3Dradio value=3D0 =
name=3DQ6></TD>
            <TD>X will burn brighter and Y will not burn.</TD></TR>
          <TR>
            <TD width=3D50><B>D</B><INPUT type=3Dradio value=3D1 =
name=3DQ6></TD>
            <TD>Y will burn brighter and X will not =
burn.</TD></TR></TBODY></TABLE><!-- <input type=3D"button" =
value=3D"Explanation" onclick=3D'gibfeedback("Only in option 2 the =
effective resistance is 6&Omega;: 4&Omega; and 4&Omega; in parallel - =
1/R =3D 1/4 + 1/4 =3D 1/2 hence R =3D 2&Omega;. 4&Omega; is in series =
with 2&Omega; hence R combined =3D 2&Omega; + 4&Omega; =3D 6&Omega;.")'>
 -->
        <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
      </TD>
      <TD><IMG height=3D228 alt=3D"electricity II, diagram 5"=20
        src=3D"http://www.sec.org.za/tests/pmcelecb05.gif" width=3D346 =
border=3D0>=20
    </TD></TR></TBODY></TABLE>
  <P><!frage7><B><FONT color=3Dred>7.)</FONT> A battery is connected to =
a small=20
  lamp. If a second identical lamp is connected in series with the =
first, what=20
  will happen to the current provided by the battery? <BR>
  <TABLE cellSpacing=3D0 cols=3D2 border=3D0>
    <TBODY>
    <TR>
      <TD width=3D50><B>A</B><INPUT type=3Dradio value=3D1 =
name=3DQ7></TD>
      <TD>it will decrease</TD></TR>
    <TR>
      <TD width=3D50><B>B</B><INPUT type=3Dradio value=3D0 =
name=3DQ7></TD>
      <TD>it will remain the same</TD></TR>
    <TR>
      <TD width=3D50><B>C</B><INPUT type=3Dradio value=3D0 =
name=3DQ7></TD>
      <TD>it will increase</TD></TR>
    <TR>
      <TD width=3D50><B>D</B><INPUT type=3Dradio value=3D0 =
name=3DQ7></TD>
      <TD>it will become zero</TD></TR></TBODY></TABLE><!-- <input =
type=3D"button" value=3D"Explanation" =
onclick=3D'gibfeedback("B<sub>2</sub> and B<sub>3</sub> are connected in =
parallel, hence only 50% of the current will flow through each of those =
bulbs and the p.d. across them will be less than the p.d. across =
B<sub>1</sub> (1/3 of total p.d. will be across B<sub>2</sub> and =
B<sub>3</sub>; 2/3 of total p.d. across B<sub>1</sub>). As a result =
B<sub>1</sub> will shine brightest (power =3D current <small>x</small> =
voltage) and B<sub>2</sub> and B<sub>3</sub> will have the same =
brightness. ")'>
 -->
  <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>

  <P><!frage8><B><FONT color=3Dred>8.)</FONT> A 200 V electrical outlet =
is=20
  protected by a circuit breaker. The circuit breaker will cut out if =
the=20
  current drawn from the outlets exceeds 16 A. A 1000 W toaster and a =
2000 W=20
  kettle can be connected to the outlet, either singly, or both in =
parallel=20
  using a double adapter. Which use of the appliances will trip the =
circuit=20
  breaker? </B>
  <TABLE>
    <TBODY>
    <TR>
      <TD vAlign=3Dtop width=3D"50%"><BR><BR>
        <TABLE cellSpacing=3D0 cols=3D2 border=3D0>
          <TBODY>
          <TR>
            <TD width=3D50><B>A</B><INPUT type=3Dradio value=3D0 =
name=3DQ8></TD>
            <TD>the toaster used on its own</TD></TR>
          <TR>
            <TD width=3D50><B>B</B><INPUT type=3Dradio value=3D0 =
name=3DQ8></TD>
            <TD>the kettle used on its own</TD></TR>
          <TR>
            <TD width=3D50><B>C</B><INPUT type=3Dradio value=3D0 =
name=3DQ8></TD>
            <TD>the toaster and the kettle together</TD></TR>
          <TR>
            <TD width=3D50><B>D</B><INPUT type=3Dradio value=3D1 =
name=3DQ8></TD>
            <TD>none of the above</TD></TR></TBODY></TABLE><!-- <input =
type=3D"button" value=3D"Explanation" onclick=3D'gibfeedback("After =
closing the switch no current will flow through X, hence it will not lit =
up (option 4) and consequently a hgher current will pass through bulb Y =
making it shine brighter.")'>
 -->
        <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
      </TD>
      <TD vAlign=3Dtop>
        <CENTER><IMG height=3D199 alt=3D"electricity II, diagram 6"=20
        src=3D"http://www.sec.org.za/tests/pmcelecb06.gif" width=3D324=20
        border=3D0></CENTER></TD></TR></TBODY></TABLE>
  <P><!frage9><B><FONT color=3Dred>9.)</FONT> Two light bulbs are marked =
230 V; 75=20
  W and 230 V; 150 W. If the first bulb has a resistance R, then the =
resistance=20
  of the second is =85 </B>
  <TABLE cellSpacing=3D0 cols=3D2 border=3D0>
    <TBODY>
    <TR>
      <TD width=3D50><B>A</B><INPUT type=3Dradio value=3D0 =
name=3DQ9></TD>
      <TD>
        <CENTER>=BC R</CENTER></TD></TR>
    <TR>
      <TD width=3D50><B>B</B><INPUT type=3Dradio value=3D1 =
name=3DQ9></TD>
      <TD>
        <CENTER>=BD R</CENTER></TD></TR>
    <TR>
      <TD width=3D50><B>C</B><INPUT type=3Dradio value=3D0 =
name=3DQ9></TD>
      <TD>
        <CENTER>2 R</CENTER></TD></TR>
    <TR>
      <TD width=3D50><B>D</B><INPUT type=3Dradio value=3D0 =
name=3DQ9></TD>
      <TD>
        <CENTER>4 R</CENTER></TD></TR></TBODY></TABLE><!-- <input =
type=3D"button" value=3D"Explanation" onclick=3D'gibfeedback("Correct =
answer is option 3 (see also question 7): 1/3 of total p.d. will be =
across single resistor R and 2/3 of total p.d. will be measured across =
resistors R in parallel. <br>2/3 &middot; 12V =3D 8V; <br>and <br>1/3 =
&middot; 12V =3D 4V across R in parallel.")'>
 -->
  <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>

  <P><!frage10><B><FONT color=3Dred>10.)</FONT> 10. Two resistors of =
resistance 2R=20
  and 3R are connected in series with a battery, which has an emf of E =
and an=20
  internal resistance R. What is the potential difference across the =
resistor of=20
  resistance 2R? </B>
  <TABLE width=3D"90%">
    <TBODY>
    <TR>
      <TD>
        <P>
        <TABLE cellSpacing=3D0 cols=3D2 width=3D"100%" border=3D0>
          <TBODY>
          <TR>
            <TD width=3D50><B>A</B><INPUT type=3Dradio value=3D1 =
name=3DQ10></TD>
            <TD>E/3</TD></TR>
          <TR>
            <TD width=3D50><B>B</B><INPUT type=3Dradio value=3D0 =
name=3DQ10></TD>
            <TD>2E/5</TD></TR>
          <TR>
            <TD width=3D50><B>C</B><INPUT type=3Dradio value=3D0 =
name=3DQ10></TD>
            <TD>E/2</TD></TR>
          <TR>
            <TD width=3D50><B>D</B><INPUT type=3Dradio value=3D0 =
name=3DQ10></TD>
            <TD>2E</TD></TR></TBODY></TABLE><!-- <input type=3D"button" =
value=3D"Explanation" onclick=3D'gibfeedback("Total internal resistance =
=3D 6 &middot; 0,2&Omega; =3D 1,2&Omega;<br>Voltage =3D 9V<br> I =3D V/R =
=3D 9/1,2 =3D 7,5A.")'>
 -->
        <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
        </P></TD>
      <TD>
        <CENTER><IMG height=3D162 alt=3D"electricity II, diagram 7"=20
        src=3D"http://www.sec.org.za/tests/pmcelecb07.gif" width=3D264=20
        border=3D0></CENTER></TD></TR></TBODY></TABLE>
  <HR color=3Dblue SIZE=3D5>

  <CENTER>
  <TABLE cellSpacing=3D0 cols=3D1 width=3D"60%" border=3D1>
    <CAPTION><B>Results</B></CAPTION>
    <TBODY>
    <TR>
      <TD>
        <CENTER><INPUT type=3Dhidden value=3Dfalse =
name=3Dbearbeitet><INPUT onclick=3Dshow() type=3Dbutton value=3D"See =
your results" name=3DButton></CENTER></TD></TR>
    <TR>
      <TD>
        <CENTER><TEXTAREA name=3Dergebnis rows=3D3 readOnly =
cols=3D50></TEXTAREA></CENTER></TD></TR>
    <TR>
      <TD>
        <CENTER><INPUT onclick=3Dshowcorrect() type=3Dbutton =
value=3D"What are the correct answers?" =
name=3DButton></CENTER></TD></TR></TBODY></TABLE></CENTER></FORM>
  <TABLE cellPadding=3D5 width=3D"60%" border=3D1>
    <TBODY>
    <TR>
      <TD><FONT color=3D#9933ff>Hint: You can do the test offline as =
well. Just=20
        click "file" from the menu, then "save" to a destination of your =
choice.=20
        But remember to open file either with windows explorer or =
internet=20
        explorer. Netscape might not be able to reload pictures offline. =

      </FONT></TD></TR></TBODY></TABLE><B>
  <DIV align=3Dright><A href=3D"http://www.sec.org.za/trmc.html">click =
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  multiple choice questions</A></DIV></B>
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src=3D"http://www.sec.org.za/physics/XBAR06.GIF"=20
  width=3D"100%" border=3D0></CENTER>
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