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Subject: Electrostatics (multiple choice questions)
Date: Wed, 29 Dec 2004 09:50:33 -0500
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<BODY text=3D#000000 vLink=3D#800080 aLink=3D#ff0000 link=3D#0000ff =
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<BLOCKQUOTE>
  <TABLE bgColor=3D#ffff00>
    <TBODY>
    <TR>
      <TD><B>Multiple Choice Online Test</B><BR>Indicate the correct =
answer by=20
        clicking on the button next to the numbers 1, 2, 3 or 4. There =
is only=20
        one correct answer per question. After you have answered=20
        <B><U>all</U></B> multiple choice questions compare your choices =
with=20
        the correct answers. </TD></TR></TBODY></TABLE>
  <HR width=3D"100%" color=3Dred SIZE=3D3>

  <CENTER>
  <H2>Electrostatics I</H2></CENTER>
  <HR width=3D"100%" color=3Dred SIZE=3D3>
  <BR>
  <FORM name=3DF><!frage1><B>1.) A plastic rod is rubbed with a dry =
piece of cloth=20
  and the rod becomes positively charged. The rod has ...</B>=20
  <UL>
    <TABLE cellSpacing=3D0 cols=3D2 width=3D"90%" border=3D0>
      <TBODY>
      <TR>
        <TD width=3D50><B>1</B> <INPUT type=3Dradio value=3D0 =
name=3DQ1></TD>
        <TD>gained electrons</TD></TR>
      <TR>
        <TD width=3D50><B>2</B> <INPUT type=3Dradio value=3D1 =
name=3DQ1></TD>
        <TD>lost electrons</TD></TR>
      <TR>
        <TD width=3D50><B>3</B> <INPUT type=3Dradio value=3D0 =
name=3DQ1></TD>
        <TD>gained protons</TD></TR>
      <TR>
        <TD width=3D50><B>4</B> <INPUT type=3Dradio value=3D0 =
name=3DQ1></TD>
        <TD>lost protons</TD></TR></TBODY></TABLE><INPUT =
onclick=3D'gibfeedback("Whether a body is positively or negatively =
charged depends only on the quantity of electrons this body is =
accommodating. Positively charged objects have lost electrons and =
negatively charged objects have gained electrons, hence number 2 is the =
correct answer.")' type=3Dbutton value=3DExplanation>
    <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
     </UL><!frage2><B>2.) A negatively charged rod will ... </B>
  <UL>
    <TABLE cellSpacing=3D0 cols=3D2 width=3D"90%" border=3D0>
      <TBODY>
      <TR>
        <TD width=3D50><B>1</B><INPUT type=3Dradio value=3D0 =
name=3DQ2></TD>
        <TD>always point north-south when freely suspended.</TD></TR>
      <TR>
        <TD width=3D50><B>2</B><INPUT type=3Dradio value=3D0 =
name=3DQ2></TD>
        <TD>attract a negative charge.</TD></TR>
      <TR>
        <TD width=3D50><B>3</B><INPUT type=3Dradio value=3D1 =
name=3DQ2></TD>
        <TD>repel a negative charge</TD></TR>
      <TR>
        <TD width=3D50><B>4</B><INPUT type=3Dradio value=3D0 =
name=3DQ2></TD>
        <TD>repel a positive charge</TD></TR></TBODY></TABLE><INPUT =
onclick=3D'gibfeedback("Option 3 is correct: Like charges repel and =
unlike charges attract.")' type=3Dbutton value=3DExplanation>
    <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
     </UL><!frage3><B>
  <TABLE border=3D0>
    <TBODY>
    <TR vAlign=3Dtop>
      <TD><B>3.) P and Q are metal spheres hanging from nylon threads. =
When a=20
        negatively charged rod is brought between them - as shown in the =
diagram=20
        to the right - P is repelled and Q is attracted by the rod. =
<BR>Which of=20
        the following statements is correct? </B>
        <UL>
          <TABLE cellSpacing=3D0 cols=3D2 width=3D"90%" border=3D0>
            <TBODY>
            <TR>
              <TD width=3D50><B>1</B><INPUT type=3Dradio value=3D1 =
name=3DQ3></TD>
              <TD>P must be negative.</TD></TR>
            <TR>
              <TD width=3D50><B>2</B><INPUT type=3Dradio value=3D0 =
name=3DQ3></TD>
              <TD>P must be positive.</TD></TR>
            <TR>
              <TD width=3D50><B>3</B><INPUT type=3Dradio value=3D0 =
name=3DQ3></TD>
              <TD>Q must be negative.</TD></TR>
            <TR>
              <TD width=3D50><B>4</B><INPUT type=3Dradio value=3D0 =
name=3DQ3></TD>
              <TD>Q must be a conductor.</TD></TR></TBODY></TABLE><INPUT =
onclick=3D'gibfeedback("Only a repulsive force between bodies is an =
indication that both bodies carry the same charge, correct number 1. NB: =
A charged object will induce charges in an uncharged object, =
consequently a force of attraction will be observed.")' type=3Dbutton =
value=3DExplanation>
          <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
           </UL></TD>
      <TD vAlign=3Dtop><IMG height=3D200 alt=3D"electrostatics I, =
diagram 1"=20
        src=3D"http://www.sec.org.za/tests/pmcestat1.gif" width=3D245=20
    border=3D0></TD></TR></TBODY></TABLE><!frage4><B>4.) There is an =
electrostatic=20
  force of attraction between any two of three metal spheres P, Q and R. =
A=20
  possible combination for the charges on P, Q and R is =85 </B>
  <UL>
    <TABLE cellSpacing=3D0 cols=3D2 width=3D"90%" border=3D0>
      <TBODY>
      <TR>
        <TD width=3D50><B>1</B><INPUT type=3Dradio value=3D0 =
name=3DQ4></TD>
        <TD>P - positive &nbsp;Q - negative &nbsp;R - positive</TD></TR>
      <TR>
        <TD width=3D50><B>2</B><INPUT type=3Dradio value=3D1 =
name=3DQ4></TD>
        <TD>P - positive &nbsp;Q - negative &nbsp;R - neutral</TD></TR>
      <TR>
        <TD width=3D50><B>3</B><INPUT type=3Dradio value=3D0 =
name=3DQ4></TD>
        <TD>P - positive &nbsp;Q - positive &nbsp;R - positive</TD></TR>
      <TR>
        <TD width=3D50><B>4</B><INPUT type=3Dradio value=3D0 =
name=3DQ4></TD>
        <TD>P - neutral &nbsp; Q - positive &nbsp;R -=20
    neutral</TD></TR></TBODY></TABLE><INPUT onclick=3D'gibfeedback("Only =
in situation 2 is the electrostatic force attractive between all =
objects. Unlike charges attract (the pos. and neg. rods) and neutral =
objects become charged by induction when they are exposed to the field =
on a charged object. (see also explanation to question 3)")' =
type=3Dbutton value=3DExplanation>
    <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
     </UL><!frage5>
  <TABLE cellSpacing=3D0 width=3D"90%" border=3D0>
    <TBODY>
    <TR>
      <TD vAlign=3Dtop><B>5.) Three metal spheres P, Q and R, on =
insulated=20
        stands carry charges as shown in the sketch. Q is now moved =
towards P=20
        and touches P. Q is then moved towards R and touches R, after =
which Q is=20
        returned to its original position.=20
        <P></B></P></TD>
      <TD vAlign=3Dtop><IMG height=3D200 alt=3D"electrostatics I, =
diagram 2"=20
        src=3D"http://www.sec.org.za/tests/pmcestat5.gif" width=3D301 =
border=3D0>=20
    </TD></TR></TBODY></TABLE><B>The charges on P, Q and R [in nC] are =
now =85 </B>
  <UL>
    <TABLE cellSpacing=3D0 cols=3D4 width=3D280 border=3D0>
      <TBODY>
      <TR>
        <TD width=3D50><B>&nbsp;</B></TD>
        <TD align=3Dmiddle width=3D70><B>P</B></TD>
        <TD align=3Dmiddle width=3D70><B>Q</B></TD>
        <TD align=3Dmiddle width=3D70><B>R</B></TD></TR>
      <TR>
        <TD width=3D50><B>1</B><INPUT type=3Dradio value=3D0 =
name=3DQ5></TD>
        <TD align=3Dmiddle width=3D70>+ 4,0 nC</TD>
        <TD align=3Dmiddle width=3D70>+ 4,0 nC</TD>
        <TD align=3Dmiddle width=3D70>+ 4,0 nC</TD></TR>
      <TR>
        <TD width=3D50><B>2</B><INPUT type=3Dradio value=3D1 =
name=3DQ5></TD>
        <TD align=3Dmiddle width=3D70>+ 4,0 nC</TD>
        <TD align=3Dmiddle width=3D70>+ 2,0 nC</TD>
        <TD align=3Dmiddle width=3D70>+ 2,0 nC</TD></TR>
      <TR>
        <TD width=3D50><B>3</B><INPUT type=3Dradio value=3D0 =
name=3DQ5></TD>
        <TD align=3Dmiddle width=3D70>+ 6,0 nC</TD>
        <TD align=3Dmiddle width=3D70>+ 3,0 nC</TD>
        <TD align=3Dmiddle width=3D70>+ 3,0 nC</TD></TR>
      <TR>
        <TD width=3D50><B>4</B><INPUT type=3Dradio value=3D0 =
name=3DQ5></TD>
        <TD align=3Dmiddle width=3D70>+ 2,5 nC</TD>
        <TD align=3Dmiddle width=3D70>+ 2,5 nC</TD>
        <TD align=3Dmiddle width=3D70>+ 2,5 =
nC</TD></TR></TBODY></TABLE><INPUT onclick=3D'gibfeedback("P and Q =
touch: +2 nC from P required to give Q a zero charge, leaving 8 nC on P =
which will be distributed equally on both charges. Hence Q has +4 nC =
after touching P. Now it touches R and after touching both spheres carry =
same charge of +2 nC.In option 2 we have the correct charge =
distribution.")' type=3Dbutton value=3DExplanation>
    <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
     </UL><!frage6>
  <TABLE width=3D"90%" border=3D0>
    <TBODY>
    <TR>
      <TD vAlign=3Dtop width=3D"50%"><B>6.) In an experiment 4 plastic =
Rods P, Q,=20
        R, S are used. Each rod may be charged or uncharged. In tests, =
it is=20
        found that P repels Q but R exerts no force on S. <BR>These =
tests show=20
        that ... </B></TD>
      <TD vAlign=3Dtop width=3D"50%"><IMG height=3D140=20
        alt=3D"electrostatics I, diagram 3"=20
        src=3D"http://www.sec.org.za/tests/pmcestat2.gif" width=3D342=20
    border=3D0></TD></TR></TBODY></TABLE>
  <UL>
    <TABLE cellSpacing=3D0 cols=3D2 width=3D"90%" border=3D0>
      <TBODY>
      <TR>
        <TD width=3D50><B>1</B><INPUT type=3Dradio value=3D0 =
name=3DQ6></TD>
        <TD>P and Q are both positive.</TD></TR>
      <TR>
        <TD width=3D50><B>2</B><INPUT type=3Dradio value=3D0 =
name=3DQ6></TD>
        <TD>P and Q are both negative.</TD></TR>
      <TR>
        <TD width=3D50><B>3</B><INPUT type=3Dradio value=3D0 =
name=3DQ6></TD>
        <TD>P and Q have opposite charges.</TD></TR>
      <TR>
        <TD width=3D50><B>4</B><INPUT type=3Dradio value=3D1 =
name=3DQ6></TD>
        <TD>R and S are uncharged.</TD></TR></TBODY></TABLE><INPUT =
onclick=3D'gibfeedback("From the given information me must conclude that =
only the forth statement is 100% correct.")' type=3Dbutton =
value=3DExplanation>
    <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
     </UL><!frage7><B>7.) Which of the diagrams below represents the =
effect of=20
  bringing a positively charged rod near (but not touching) an =
electroscope.</B>
  <P>
  <CENTER><IMG height=3D236 alt=3D"electrostatics I, diagram 4"=20
  src=3D"http://www.sec.org.za/tests/pmcestat3.gif" width=3D622 =
border=3D0></CENTER>
  <UL>
    <TABLE cellSpacing=3D0 cols=3D2 width=3D"90%" border=3D0>
      <TBODY>
      <TR>
        <TD width=3D50><B>1</B><INPUT type=3Dradio value=3D0 =
name=3DQ7></TD>
        <TD><B>1</B></TD></TR>
      <TR>
        <TD width=3D50><B>2</B><INPUT type=3Dradio value=3D0 =
name=3DQ7></TD>
        <TD><B>2</B></TD></TR>
      <TR>
        <TD width=3D50><B>3</B><INPUT type=3Dradio value=3D1 =
name=3DQ7></TD>
        <TD><B>3</B></TD></TR>
      <TR>
        <TD width=3D50><B>4</B><INPUT type=3Dradio value=3D0 =
name=3DQ7></TD>
        <TD><B>4</B></TD></TR></TBODY></TABLE><INPUT =
onclick=3D'gibfeedback("The positively charged rod will induce negative =
charges in the upper part of the electroscope (electrons will flow =
towards the metal cap of the electroscope), which is shown in situation =
3.")' type=3Dbutton value=3DExplanation>
    <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
     </UL><!frage8><B>8.) An electroscope is negatively charged, with =
the leaf at=20
  an angle of about 45<SUP>o</SUP>. When a negatively charged rod is =
slowly=20
  brought near the plate of the electroscope, the leaf ... </B>
  <UL>
    <TABLE cellSpacing=3D0 cols=3D2 width=3D"90%" border=3D0>
      <TBODY>
      <TR>
        <TD width=3D50><B>1</B><INPUT type=3Dradio value=3D1 =
name=3DQ8></TD>
        <TD>rises.</TD></TR>
      <TR>
        <TD width=3D50><B>2</B><INPUT type=3Dradio value=3D0 =
name=3DQ8></TD>
        <TD>falls.</TD></TR>
      <TR>
        <TD width=3D50><B>3</B><INPUT type=3Dradio value=3D0 =
name=3DQ8></TD>
        <TD>rises then falls.</TD></TR>
      <TR>
        <TD width=3D50><B>4</B><INPUT type=3Dradio value=3D0 =
name=3DQ8></TD>
        <TD>falls to zero then rises.</TD></TR></TBODY></TABLE><INPUT =
onclick=3D'gibfeedback("Unlike charges repel, hence the repulsive force =
between leave and metal plate/rod will increase causing the leave to =
rise even more.")' type=3Dbutton value=3DExplanation>
    <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
     </UL><!frage9><B>9.) An electroscope is negatively charged, with =
the leaf at=20
  an angle of about 45<SUP>o</SUP>. A metal ball on an insulating handle =
is=20
  slowly brought to (but not touching) the plate of the electroscope and =
the=20
  leaf falls.<BR>This suggests that the metal ball is </B>
  <UL>
    <TABLE cellSpacing=3D0 cols=3D2 width=3D"90%" border=3D0>
      <TBODY>
      <TR>
        <TD width=3D50><B>1</B><INPUT type=3Dradio value=3D1 =
name=3DQ9></TD>
        <TD>uncharged or positively charged.</TD></TR>
      <TR>
        <TD width=3D50><B>2</B><INPUT type=3Dradio value=3D0 =
name=3DQ9></TD>
        <TD>uncharged or negatively charged.</TD></TR>
      <TR>
        <TD width=3D50><B>3</B><INPUT type=3Dradio value=3D0 =
name=3DQ9></TD>
        <TD>positively charged.</TD></TR>
      <TR>
        <TD width=3D50><B>4</B><INPUT type=3Dradio value=3D0 =
name=3DQ9></TD>
        <TD>negatively charged.</TD></TR></TBODY></TABLE><INPUT =
onclick=3D'gibfeedback("Only in situation 1 electrons will flow towards =
the top of the electroscope (and as a result the deflection of the leaf =
will decrease) either because of the presence of a positively charged =
body or because of inducing positive charges in the part of the sphere =
which is facing the negatively charged electroscope.")' type=3Dbutton =
value=3DExplanation>
    <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
     </UL><!frage10>
  <TABLE>
    <TBODY>
    <TR>
      <TD vAlign=3Dtop><B>10.) A pear shaped conductor stands on an =
insulated=20
        base as shown in the diagram at the right.<BR><BR>If the =
conductor is=20
        given some charge at P, </B>
        <UL>
          <TABLE cellSpacing=3D0 cols=3D2 width=3D"90%" border=3D0>
            <TBODY>
            <TR>
              <TD width=3D50><B>1</B><INPUT type=3Dradio value=3D1 =
name=3DQ10></TD>
              <TD>all charge resides on the surface of the =
conductor.</TD></TR>
            <TR>
              <TD width=3D50><B>2</B><INPUT type=3Dradio value=3D0 =
name=3DQ10></TD>
              <TD>the charge distribution is equal all over the =
sphere.</TD></TR>
            <TR>
              <TD width=3D50><B>3</B><INPUT type=3Dradio value=3D0 =
name=3DQ10></TD>
              <TD>the charge density (amount of charge per unit area) is =

                highest at Q.</TD></TR>
            <TR>
              <TD width=3D50><B>4</B><INPUT type=3Dradio value=3D0 =
name=3DQ10></TD>
              <TD>the charge density is highest at =
P.</TD></TR></TBODY></TABLE><INPUT onclick=3D'gibfeedback("All charge =
given to a conductor resides on its surface, the charge density is =
highest at sharp points and there is no charge inside a hollow =
conductor.")' type=3Dbutton value=3DExplanation>
          <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
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