The circuit consists of a loop ACDF with no branches, as a result there is only one current in the whole loop. On each side of the loop there are components: an EMF, an Ammeter which measures the current through that loop, a resistor, and a Voltmeter which measures the potential rise/drop on the resistor. The values for each of the components can be seen either next to or written on the components themselves. It should be made clear that the Ammeters and Voltmeters are positioned in such a way that they will show a positive reading when the current is flowing from top to bottom, although such a selection is made in this circuit it would have been just as correct to pick it's opposite.

Only two rules/formulas are needed to solve the system of equations envolved:

To solve the equation we will need to name our components, we have
chosen a system in which each component is named by a letter
indicating it's type (**I** for current, **E** for the
EMF, and **R** for resistance) and a subletter indicating it's
branch (A or C). Thus the current in the leftmost branch would be
(by **Ohm's Law**):
**I = V _{A}/R_{A}**.

We apply the **Loop Rule**, which says
that the sum of the potential rises must equal to the sum of the
potential drops i.e.,

**
E _{A} + I*R_{A} + I*R_{C} =
E_{C};
**

I = (E_{C} - E_{A})/(R_{A} + R_{C});

Therefore, since the resistance, **R**, and the EMF, **E**, are
known for each side, the currents, **I**, are calculated by the
above method.

The voltage across the resistors is arrived at as follows: (let
**V** be the voltage across the resistor, by Ohm's Law)

** V = IR; **

Last modified: June 20, 1997