**Far point**: For an object at infinity, the corrective lens must produce a virtual image at the
uncorrected far point.

i.e., 1/p + 1/q = P

1/inf + 1/q = -2.25 diopters

q = -0.44 m

Therefore the uncorrected far point is at 0.44 m

**Near Point**; For an object at 0.25 m, the lens produces a virtual image at the uncorrected near
point.

i.e., 1/p + 1/q = P

1/0.25 + 1/q = -2.25 diopters

q = -0.16 m

Therefore the uncorrected near point is at 0.16 m

The answer is D