P = (2/l)sin2(npx/l)

= (2/1.05)sin2[3p (6/7)l]/l, at the 7th carbon

P = (2/1.05)sin2(3/2)(6/7)2p = (2/1.05)sin2(9/7)2p = (2/1.05)sin2(9/7)360º

= (2/1.05)sin2462.86º = 1.905(0.9505) = 1.81 nm-1

Answer is B

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