# Problem 10-38 Addition of Electric fields - Part 2 - B

Two negative charges have locations as shown in the Figure. Charge $q_1$ is  $-3.6\times 10^{-8} C;$ charge $q_2$ is  $-5.2 \times10^{-8} C.$ What is the electric field (magnitude and direction) at (a) $\text{point A}$? (b) $\text{point B}$?

Accumulated Solution

$|E_1| = k|q_1|/r_1{^2}$

Correct.

Before continuing, calculate the value of  $|E_1| .$ The value of $k$ is $8.99 \times 10^9\; Nm^2/C^2$

Continue.