# Problem 10-38 Addition of Electric fields - Part 2 - C

Two negative charges have locations as shown in the Figure. Charge $q_1$ is  $-3.6\times 10^{-8} C;$ charge $q_2$ is  $-5.2 \times10^{-8} C.$ What is the electric field (magnitude and direction) at (a) $\text{point A}$? (b) $\text{point B}$?

Accumulated Solution

No. The equation for the electric field is just another form of  Coulamb's Law for the force between 2 charges $(F = kqq'/r^2)$ except the field is defined as the "force per unit charge" (i.e.divide through by one of the charges. Look at the choices again.

Try again.