Problem 10-38 Addition of Electric fields - Part 2 - Positive

Diagram of two negative charges.

Two negative charges have locations as shown in the Figure. Charge \(q_1\) is  \(-3.6\times 10^{-8} C;\) charge \(q_2\) is  \(-5.2 \times10^{-8} C.\) What is the electric field (magnitude and direction) at (a) \(\text{point A}\)? (b) \(\text{point B}\)?


Correct. Since \(q_1\) is negative the force (and therefore the field) will be

\(\text{away from} \; q_1\)

\(\text{toward} \; q_1\)