Problem 10-38 Addition of Electric fields - Part 3 - B

Diagram of two negative charges.

Two negative charges have locations as shown in the Figure. Charge \(q_1\) is  \(-3.6\times 10^{-8} C;\) charge \(q_2\) is  \(-5.2 \times10^{-8} C.\) What is the electric field (magnitude and direction) at (a) \(\text{point A}\)? (b) \(\text{point B}\)?

Accumulated Solution

Diagram B of direction of field.

\( |E_1| = k|q_1|/r_1{^2} \\ |E_1| = k|q_1|/r_1{^2} = 2.24 \times 10^{13} \; N/C\)

Diagram indicating electric field moving to the right.

Correct, to the right.

Before continuing, calculate the magnitude of the field \(E_2.\) The value of \(k\) is \(8.99 \times10^9\; Nm^2/C^2.\)

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