Problem 11-35 Potential and kinematics - Part 3B - C
A proton is accelerated from rest from a positively charged plate to a parallel negatively charged plate. The separation of the plates is \(8.9\; mm.\) If the potential difference between the plates is \(75.3\; V,\) what is the speed of the proton just as it hits the negative plate?
[Ans. \(1.2 \times 10^5\; m/s\)]
Accumulated Solution
No. The equation is incorrect; you can see this with a simple dimensional analysis. The units of \(V\) are joules/coulomb and of \(q\) are coulombs. What are the units of \(q/V\)? Is \(q/V\) an energy?