Problem 2-86 Linear Kinematics - Part 2 - (c)
A bicyclist, traveling at \(4.0 \;km/h\) at the top of a hill coasts downward with constant acceleration, reaching a speed of \(33 \;km/h\) in \(33 \;s.\) What distance, in metres, does the cyclist travel in that time?
No. But it is an interesting and useful exercise if you know the conversion factors.
For your interest here is the conversion for \(4\; km/h\)
\(4\frac{km}{h} \times \frac{1 \; mi}{1.6 \; km} \times 8 \frac{\text{furlongs}}{mi} \times 24 \frac{h}{\text{day}}\times 14 \frac{\text{day}}{\text{ft'nt}} \\ = 6720 \frac{\text{furlongs}}{\text{fortnight}}\)