Problem 2-86 Linear Kinematics - Part 2 - (c)

A bicyclist, traveling at \(4.0 \;km/h\) at the top of a hill coasts downward with constant acceleration, reaching a speed of \(33 \;km/h\) in \(33 \;s.\) What distance, in metres, does the cyclist travel in that time?

diagram of a cyclist on a hill

No. But it is an interesting and useful exercise if you know the conversion factors.
For your interest here is the conversion for \(4\; km/h\)

\(4\frac{km}{h} \times \frac{1 \; mi}{1.6 \; km} \times 8 \frac{\text{furlongs}}{mi} \times 24 \frac{h}{\text{day}}\times 14 \frac{\text{day}}{\text{ft'nt}} \\ = 6720 \frac{\text{furlongs}}{\text{fortnight}}\)


Try again.