# Problem 3-25b - Vector difference -Part 3 - (B)

Determine the vector that must be added to the sum of $A$ and $B$ in the figure to give a net displacement of $4.0\; km\; \text{W}$.

Accumulated Solution

Solution $A_x$ $B_x$ $C_x$ $R_x$
(A) $5.1 \cos 71$ $6.8 \sin 52$ $C_x$ $-4$

Solution $A_y$ $B_y$ $C_y$ $R_y$
(B) $-5.1 \sin 71$ $6.8 \cos 52$ $C_y$ $0$

Correct!

So the required component sums are:
$5.1 \cos71 + 6.8 \sin52 + C_x = -4 \\ -5.1 \sin71 + 6.8 \cos52 + C_y = 0$

Work out $C_x$ and $C_y$ before continuing.

Continue.