# Problem 4-11 - Free fall - Part 12 - (D)

A ball is thrown from a balloon with an initial unknown velocity. The ball accelerates at $9.80\;m/s^2$ downward for $2.00\; s$, at which time its instantaneous velocity is $24.0\; m/s$ at an angle of $45.0^\circ$ below the horizontal. Determine the magnitude and direction of the initial velocity.

Accumulated Solution

$v = v_0 + at$

$v_x = v_{0x} + a_xt \\ v_y = v_{0y} + a_yt \\ a_x = 0 \\ a_y = g \\ v_x = v_{0x} \\ v_y = v_{0y} + 9.8t \\ v_x = 24 \cos45 = 17.0\; m/s \\ v_y = 24 \cos45 = 17.0\; m/s \\ v_{0x} = v_{0x} = 17.0 \; m/s \\ v_{0y} = -2.6 \; m/s \\ v_0 = 17.2 \; m/s$

No. That is the wrong function.

Try again.