# Problem 4-57 Projectile - Part 3 - A

An astronaut strikes a golf ball on the Moon where the magnitude of the acceleration due to gravity is $1.6\; m/s^2.$ The ball takes off with a velocity of $32\; m/s$ at an angle $35^\circ$ above the horizontal (the moon’s horizontal) and lands in a valley $15\; m$ below the level where it started. Determine the golf ball's: (a) maximum height (b) time of flight (c) horizontal distance traveled.
[Ans. (a) $1.1 \times 10^2\; m$   (b) $24\; s$   (c) $6.2 \times 10^2\; m$]

Accumulated Solution

$x$ $y$
- -

Correct!

There is no acceleration horizontally.
The appropriate equation for this motion is:

(A)   $x = v_{0x{^t}}$

(B)   $x = v_{0x{^t}} + ½ \;a_xt^2$

(C)   $v_x{^2} = v_{0x{^2}} + 2a_xx$