# Problem 6-4 Friction coefficients - Part 2 - A

The coefficients of friction between a stove of mass $65\; kg$ and the horizontal floor beneath it are: static, $0.71$; kinetic, $0.64$.

(a) What is the minimum horizontal force that must be applied to the stove to set it in motion?
(b) Once the stove is moving, what magnitude of horizontal force will keep it moving at constant velocity?

Accumulated Solution

Correct!

The friction force is given by:

(A) $f_s = \mu_sF_N$

(B) $f_k = \mu _kF_N$