The only thing that relates directly to
sample length and concentration is the absorbance A = ecl,
so A must be found.

%T = 48, therefore I/I_{0} = 0.48

A = log(1/0.48) = 0.319 = ecl

If l is increased by a factor 3 then so must be the absorbance.

A_{new} = 3X0.319 = 0.956 = log I_{0}/I

I_{0}/I = 9.04

I/I_{0} = 0.11

%T = 11%
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