Yes! 1/Req = 1/R2 + 1/R3 = 1/2500 + 1/10000 = 4X10-4 + 1X10-4 = 5X10-4
Req = 1/5X10-4 = 2000 W
Since the current I = 1X10-3 A goes through this resistance the voltage across it (and thus across both R2 and R3) is
VBC = IReq = 1X10-3X2000 = 2 V.

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