One point is labeled "a" and two loops 1 and 2.
Using the point rule at a: I1 + I2 + I3 = 0
Using the loop rule in 1: 6 - 2I1 - 12(-I3) = 0
Using the loop rule in 2: 8 + 12I3 = 0
Therefore I3 = 8/12 = 2/3 A
Subsitute in loop 1: 6 - 2I2 + (2/3)12 = 0
2I1 = 6 + 8 = 14
I1 = 7 A
From point rule: I2 = -I1 - I3 = -7 2/3 A

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