Now find the probability density (probability per unit length) at the position of the 10th atom.

Where l = 11b, n = 3 and x = 9b

y

= 1.21 sin

= 1.21 sin

= 1.21 sin

= 1.21 X (0.99)

Probability of finding the electron in a distance 0.0050 nm centered
at the 10th atom

= 1.19 nm^{-1} X 0.0050 nm = 5.9X10^{-3}