We must first determine the electronic configuration of the ground state. In this case there are 6 electrons.

 The highest filled level is that for which n = 1

 The circumference, L,  of the circle is given by:
L = 6 X 0.15 nm = 0.75 nm

 The energy for a circular molecule is:
E = n 2h2/2mL2
E = 12(6.63X10-34)2 / 2(9.11X10-31)(0.75X10-9)2
= 4.3 X 10-19 J

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