Biophysics Problem 24

By modifying the example on the standing vertical jump, determine an expression for the vertical height attained during a jump at an angle \(\theta\) to the horizontal.

This refers to the material on page 95 of the text, where the vertical height attained for a jump straight up with an initial velocity \(v\) is shown.

 Assume that the jump is now made with initial speed \(v\) at the angle \(\theta.\)

 The initial vertical velocity will then be \(v \sin\theta.\)

 You should then be able to get  \(h = v^2 \sin^2 \theta / 2g\)