# Problem 11-46 Current and potential change - Part 2

In a particular lightning bolt, $24 \;C$ of charge are transferred in $0.21\; s$ through a potential difference of $5.5 \times10^8\; V.$

(a) What is the average current?
(b) How much electric potential energy is dissipated?

$I = q/t = 24 C/0.21\; s = 1.1 \times 10^2 A \quad \text{(answer to part (a))}$

The relationship between change in potential energy $(\Delta U)$, potential difference $(\Delta V)$ and charge $q$ is:

(A)   $\Delta U = q \Delta V$

(B)   $\Delta V = q \Delta U$

(C)    $q = \Delta V \Delta U$