Problem 11-46 Current and potential change - Part 3

In a particular lightning bolt, \(24 \;C\) of charge are transferred in \(0.21\; s\) through a potential difference of \(5.5 \times10^8\; V.\)

(a) What is the average current?
(b) How much electric potential energy is dissipated?

Accumulated Solution

\(I = q/t = 24 \;C/0.21\; s = 1.1 \times 10^2\; A \quad \text{(answer to part (a))} \\ \Delta U = q\Delta V\)

\(\Delta U = q \Delta V = 24(5.5 \times 10^8 ) = 1.3 \times 10^{10}\; J \quad \text{(answer to part (b))}\)

You have completed this problem.