# Problem 2-43 - Free fall - Part 3 (b)

A baseball pitcher throws a ball vertically straight upward and catches it $4.2\; s$ later. (a) With what velocity did the ball leave the pitcher's hand? (b) What was the maximum height reached by the ball?

Correct!

We know the acceleration ($\mathrm{9.8\; m/s^2}$ down), the time of flight ($4.2\; s$) and the displacement.

The displacement is:

(A)  $\mathrm{2\times \;the \;distance\; the\; ball \;rises}$

(B)  $\mathrm{9.8\; m}$

(C)  $\mathrm{0}$