Problem 2-43 - Free fall - Part 8 (b)
A baseball pitcher throws a ball vertically straight upward and catches it \(4.2\; s\) later. (a) With what velocity did the ball leave the pitcher's hand? (b) What was the maximum height reached by the ball?
Accumulated solution
\(\mathrm{t = 4.2 \;s \\ a_y = -9.8\; m/s^2 \\ v_y = -v_{0_y}}\)
Time to rise to maximum height \(\mathrm{= 2.1\; s}\)
\(\mathrm{v_{0_y} = 21\; m/s}\)
No. The velocity at maximum height is zero.