# Problem 2-86 Linear Kinematics - Part 3

A bicyclist, traveling at $4.0\; km/h$ at the top of a hill coasts downward with constant acceleration, reaching a speed of $33 \;km/h$ in $33 \;s.$ What distance, in metres, does the cyclist travel in that time?

You should have:

$v_0 = 4 \frac{km}{h} \times \frac{10^2}{km}\times \frac{1\; h}{3600\; s} = 1.11\; m/s \\ v = 33\frac{km}{h} = \frac{1.11}{4} 33 = 9.17 \; m/s$

The appropriate method to follow is:

(A)   We need to find the acceleration before we can solve for the distance using the Galilean equations.

(B)   We can solve the problem without finding the acceleration.