Problem 2-86 Linear Kinematics - Part 3

A bicyclist, traveling at \(4.0\; km/h\) at the top of a hill coasts downward with constant acceleration, reaching a speed of \(33 \;km/h\) in \(33 \;s.\) What distance, in metres, does the cyclist travel in that time?

diagram of a cyclist on a hill

You should have: 

\(v_0 = 4 \frac{km}{h} \times \frac{10^2}{km}\times \frac{1\; h}{3600\; s} = 1.11\; m/s \\ v = 33\frac{km}{h} = \frac{1.11}{4} 33 = 9.17 \; m/s\)

The appropriate method to follow is:

(A)   We need to find the acceleration before we can solve for the distance using the Galilean equations.

(B)   We can solve the problem without finding the acceleration.