Problem 2-95 Linear Kinematics - Part 4 - (b)
A camera is set up to take photographs of a ball undergoing vertical motion. The camera is \(5.2 \;m\) above the ball launcher, which can launch the ball with an initial velocity of \(17 \;m/s\) upward. Assuming that the ball goes straight up and straight down past the camera, at what times will the ball pass the camera?
Accumulated Solution
\(y = v_{0^t} + (1/2)at^2 \\ 5.1 = 17t - 4.9t^2 \\ y = \frac{-b}{2a} \pm \frac{\sqrt{b^2 - 4ac}}{2a}\)
Correct!
Substitute the numerical values in the equation and solve for \(t\) before you continue.