Problem 4-62 Centripetal acceleration - Part 4 - B
An astronaut in training is spinning around in a device that rotates at 30 revolutions per minute. (a) If the astronaut is \(7.5\; m\) from the centre of the device, what is the magnitude of the centripetal acceleration? (b) Express the answer in terms of "\(g,\)" the magnitude of the acceleration due to gravity.
[Ans. (a) \(74\; m/s^2\) (b) \(7.6\; g\)]
Accumulated Solution
The expression for centripetal acceleration is: \(a_c = v^2/r\)
\(\text{The speed} \; v = d/t \; \text{where}\; d = 47.1 \;m \)
No. \(30\) is the number of revolutions in \(1\) minute.