Problem 4-62 Centripetal acceleration - Part B4 - B
An astronaut in training is spinning around in a device that rotates at 30 revolutions per minute. (a) If the astronaut is \(7.5\; m\) from the centre of the device, what is the magnitude of the centripetal acceleration? (b) Express the answer in terms of "\(g,\)" the magnitude of the acceleration due to gravity.
[Ans. (a) \(74\; m/s^2\) (b) \(7.6\; g\)]
Accumulated Solution
The expression for centripetal acceleration is: \( a_c = 4\pi ^2r/T^2\)
The period \(T = 2 \;s\)
Centripetal acceleration \(a_c = 74\; m/s^2\)
Correct!
Expressed in \(g’s\), \(a = 74 (m/s^2) \times (1/9.8) (g/m/s^2) = 7.6\; g\)
You have completed this problem.