Problem 4-72 Centripetal acceleration - Part 2 - B

To produce artificial gravity on a space colony, it is proposed that the colony should rotate. Suppose that the acceleration required is equal in magnitude to the acceleration due to gravity on the earth. For a colony that is \(1.0 \;km\) in diameter, determine the frequency of rotation, the period of rotation, as well as the speed of a person at the edge of the colony (relative to the centre of the colony). [Ans. \(2.2 \times 102\; Hz;\) \(45\; s;\) \(7.0 \times 101 \;m/s\)]

Accumulated Solution

\(a_c = v^2/r \\ a = 9.8 m/s^2\)


The numerical value of \(r\) in this problem is:

(A)    \(1.0\)

(B)    \(1.0\times10^3\)

(C)    \(0.5\times10^3\)