# Problem 7-83 Power - Part 2 - A

A $2.65-kW$ motor is used to lift crates vertically upward in a factory. What is the maximum speed at which a crate of mass $147\; kg$ can be lifted by this motor? Assume that all the motor's power goes into lifting. (Hint: determine the height that the crate can be lifted in $1.00\; s$.) [Ans. $1.84\; m/s$]

Accumulated Solution

$P = 2.65\times10^3\; W$

Correct!

$P = E/t$ or $E = Pt$

In 1.0 second the energy used is:

(A) $2.65 \;J$

(B) $2.65\times10^3\; J$

(C) $0$