Problem 7-83 Power - Part 2 - A

A \(2.65-kW\) motor is used to lift crates vertically upward in a factory. What is the maximum speed at which a crate of mass \(147\; kg\) can be lifted by this motor? Assume that all the motor's power goes into lifting. (Hint: determine the height that the crate can be lifted in \(1.00\; s\).) [Ans. \(1.84\; m/s\)]


Accumulated Solution
 
\(P = 2.65\times10^3\; W\)


Correct!

\(P = E/t\) or \(E = Pt\)
 
In 1.0 second the energy used is:

(A) \(2.65 \;J\)

(B) \(2.65\times10^3\; J\)

(C) \(0\)