Problem 7-83 Power - Part 4 - B

A \(2.65-kW\) motor is used to lift crates vertically upward in a factory. What is the maximum speed at which a crate of mass \(147\; kg\) can be lifted by this motor? Assume that all the motor's power goes into lifting. (Hint: determine the height that the crate can be lifted in \(1.00\; s\).) [Ans. \(1.84\; m/s\)]

Accumulated Solution
 
\(P = 2.65\times10^3\; W \\ E = Pt\\E = 2.65\times 10^3\; J\)

Correct!

\(\text{In}\; 1.0 \;s, 2.65\times 10^3\; J = mgh = (147\; kg)(9.8\; m/s^2)h \\ h = 1.84\; m\; \text{ in} \; 1.0\;s \\ \text{i.e.,} \; v = 1.84\; m/s\)

You have completed this problem.