Problem 4-57 Projectile - Part 2 - A

An astronaut strikes a golf ball on the Moon where the magnitude of the acceleration due to gravity is \(1.6\; m/s^2.\) The ball takes off with a velocity of \(32\; m/s\) at an angle \(35^\circ\) above the horizontal (the moon’s horizontal) and lands in a valley \(15\; m\) below the level where it started. Determine the golf ball's: (a) maximum height (b) time of flight (c) horizontal distance traveled.
[Ans. (a) \(1.1 \times 10^2\; m\)   (b) \(24\; s\)   (c) \(6.2 \times 10^2\; m\)]

Accumulated Solution

Accumulated solution indicating all angles, directions and dimensions.

\(x\) \(y\)
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We have chosen the origin at the launch point and \(x\) and \(y\) in the simplest possible way.
Again we will use the double-column method of keeping track of the \(x\) and \(y\) parts of the solution

Let's deal with \(x\) first.

In the \(x\)-direction the motion is:

(A)  at constant velocity.

(B)  accelerated.