Problem 4-57 Projectile - Part 2 - A
An astronaut strikes a golf ball on the Moon where the magnitude of the acceleration due to gravity is \(1.6\; m/s^2.\) The ball takes off with a velocity of \(32\; m/s\) at an angle \(35^\circ\) above the horizontal (the moon’s horizontal) and lands in a valley \(15\; m\) below the level where it started. Determine the golf ball's: (a) maximum height (b) time of flight (c) horizontal distance traveled.
[Ans. (a) \(1.1 \times 10^2\; m\) (b) \(24\; s\) (c) \(6.2 \times 10^2\; m\)]
We have chosen the origin at the launch point and x and y in the simplest possible way.
Again we will use the double-column method of keeping track of the \(x\) and \(y\) parts of the solution
Let's deal with \(x\) first.
In the \(x\)-direction the motion is:
(A) at constant velocity.