# Problem 4-57 Projectile - Part 2 - A

An astronaut strikes a golf ball on the Moon where the magnitude of the acceleration due to gravity is \(1.6\; m/s^2.\) The ball takes off with a velocity of \(32\; m/s\) at an angle \(35^\circ\) above the horizontal (the moon’s horizontal) and lands in a valley \(15\; m\) below the level where it started. Determine the golf ball's: (a) maximum height (b) time of flight (c) horizontal distance traveled.

[Ans. (a) \(1.1 \times 10^2\; m\) (b) \(24\; s\) (c) \(6.2 \times 10^2\; m\)]

**Accumulated Solution**

\(x\) | \(y\) |
---|---|

- | - |

Correct!

We have chosen the origin at the launch point and \(x\) and \(y\) in the simplest possible way.

Again we will use the double-column method of keeping track of the \(x\) and \(y\) parts of the solution

Let's deal with \(x\) first.

In the \(x\)-direction the motion is:

(A) at constant velocity.

(B) accelerated.